leanprover-community/mathlib4
View on GitHubProve that inversion is discontinuous at the center
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#5,939 opened on Jul 16, 2023
good first issuet-analysist-euclidean-geometryt-topology
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Description
- Prove
Tendsto (inversion c R) (𝓝[≠] c) coboundedifR ≠ 0. - Deduce that
inversion c Ris discontinuous atcifR ≠ 0and the vector space is nontrivial. - Deduce that
fderiv (inversion c R) cis zero, thusfderiv (inversion c R) x = ((R / dist x c) ^ 2 • (reflection (ℝ ∙ (x - c))ᗮ : F →L[ℝ] F)) xfor allx(see #5937 for the casex ≠ c).